if the perimeter of the 3 rectangle of a cuboid is x,y,z then what is the volume of the cuboid.
(i dont remember the value of x,y,z)

• 2(a+b)=x
  2(b+c)=y
  2(c+a)=z
  Solve these three equations.
  You will get 4a=x-y+z
  Find a,b,c
  Then volume=abc
• 7 years agoHelpfull: Yes(2) No(1)
• 2(l+b)=x
  2(b+h)=y
  2(h+l)=z
  4(l+b+h)=x+y+z
  then you can find the value of l,b,h
  and the volume =l*h*b
• 7 years agoHelpfull: Yes(2) No(0)
• Let the side be a,b,c.
  First divide the values by 2 so that you get the sum of each unique pair of edges(a+b, a+c, b+c).
  
  now add 2 of these and subtract the third for all 3 combos, that is
  x/2+y/2-z/2,
  x/2+z/2-y/2 and
  y/2+z/2-x/2.
  
  this will give you double of each edge, divide these by 2 and you are have all the edges of teh cuboid
• 7 years agoHelpfull: Yes(1) No(0)
• l*b=x .....(1)
  b*h=y .......(2)
  l*h=z ..........(3)
  because having only this three combination of area.
  now,
  l*b*h=volume of cuboid
  (l^2 *b^2*h^2)^1/2=volume of cuboid .......(4)
  so, by equation 1,2,3&4
  we get
  (x*y*z)^1/2=volume of cuboid
  volume
• 7 years agoHelpfull: Yes(1) No(9)