A shopkeeper gives two successive discounts of 10% and 20% on the marked price of 5000 of a bycle, he
had to give a further discount equal to 20% of his cost price on his new selling price, as a result of which he
made neither a profit nor a loss. Find the cost price of the bycle

• This is the way I have worked out..
  10% Discount on S(Selling Price) so Price is 90% of S
  Again 20% Discount on Above so now price is 80% of 90% of S = 72% of S
  
  Now, Further Discount is in term of C(Cost Price) so 20% of C.
  
  Now 72% of S - 20% of C = C (since he made no profit no loss)
  so 72% of S = 1200% of C
  so Cost Price = (72/120)* S
  but S = 5000
  So by substituting you get 3000
• 7 years agoHelpfull: Yes(34) No(8)
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• Net discount after two successive discount= (10+20)-(10*20)/100=28%
  So new selling price = (100-28)% of S=72% of S
  
  Now, further discount on cost price= 20% C
  
  as the shopkeeper made no profit and loss,
  
  72% of S- 20% of C = 100% of C
  or, 72% of S = 120% C
  or, C = (72/120)* 5000
  
  or, C = 3000
• 6 years agoHelpfull: Yes(11) No(0)
• 3000 is the answer
• 7 years agoHelpfull: Yes(6) No(1)
• 72%of s - 20%of c = c
  72%s =120%c
  s=5000
  72%of 5000=120%of c
  3600=120/100 *c
  c=3000
• 6 years agoHelpfull: Yes(5) No(0)
• 10% 5000=500, 20% 4500=900, sp=3600, So, x+(x/5)=3600,
  x=3000 ANS
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• how u got the 1200%
• 7 years agoHelpfull: Yes(0) No(3)
• The answer should be 2000:
  
  market price = p = 5000
  cost price = c
  1) first-round discounts = 10% + 20% = 0.9*0.8 = 0.72 ==>
  the price after first-round discounts = 0.72*p = 0.72 * 5000 = 3600 = p'
  2) the second-round discount is 20% of the cost price = 0.8*c ==>
  the price after the second-discount = p'- 0.8*c = 0.72*p - 0.8*c
  Now neither profit, nor loss: final price (after the second-round discount) = cost price ==>
  0.72*p - 0.8*c = c ==>
  0.72*5000 - 0.8*c = c ==> 3600 = 1.8*c ==>
  c = 2000
• 6 years agoHelpfull: Yes(0) No(3)
• SP after successive discount =5000*0.9*0.8=3600.
  
  therefore CP=SP/1+0.2=3600/1.2=3000
• 5 years agoHelpfull: Yes(0) No(0)