Find the probability that the randomly chosen positive divisor of 10^99 is an integral multiple of 10^88.Don't have ans so not marked it....pls explain !!

1) 9/625
2) 16/625
3) 49/625
4) None of these

• 10^99 = 2^99 * 5^99 Hence total Divisor = (99 + 1)(99 + 1) = 100 * 100 = 10000
  10^99/10^88 = 10^11
  10^11 = 2^11 * 5^11 Hence total Divisor = (11 + 1)(11 + 1) = 12 * 12 = 144
  
  Probability = 144/10000 = 9/625
  option 1 is correct
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