A dishonest milkman adds 20% water to the existing quantity of milk and sells it at the same price at which he buys it.After selling a few liters he is caught and made to pay 200. He realizes that he has suffered a loss of 100 because of it.How many liters did he sell if he bought pure milk at 10/lt ?

1) 100
2) 85
3) 50
4) 60

• Existing quantity of milk = Q litre
  
  Added 20 % water = (20/100)Q = 0.2Q litre
  
  Total Mixture = Q+ 0.2Q = 1.2Q litre
  
  Cost Price = 10Q Rs
  
  Selling Price = 1.2Q * 10 = 12Q Rs
  
  Profit = 2Q Rs
  
  Fine = 200 Rs
  profit - fine = net profit
  
  Loss = 100 Rs = - 100 Rs net profit
  
  2Q - 200 = - 100
  
  => 2Q = 100
  
  => Q = 50
  
  Total Mixture = 1.2Q = 60 Litre
  option 4 is correct
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