a ,b and c can do a piece of work in 30,20 and 10 days respt.a is assisted by b on one day and by c on the other day alternately.how long would it take to finish the work?

• a can do 2 units of total work in a day
  b can do 3 units of total work in a day
  c can do 6 units of total work in a day
  
  and so when a and b will work together, they will complete 5 units of total work in a day
  while a and c working together, perform 8 units of total work.
  hence it will take 75/8 days to complete the task.
• 7 years agoHelpfull: Yes(3) No(2)
• given
  a=30
  b=20
  c=10
  let work =60 unit
  a=2unit/day
  b=3unit/day
  c=6unit/day
  according to question a+b come than a+c
  a+b=5unit/day
  a+c=8unit/day
  we have 1 tuples (5+8)/2day
  13unit/2day
  we have total work 60 unit
  than we to take 60/13=4*2=8day
  and remaining 8 unit 1 day cover a+b=5 unit and remaining 3 unit (a+c) and we know that a+c in one day finish 8 unit so 3 unit take 3/8 day
  so overall ans=8+1+3/8 =75/8 and
• 3 years agoHelpfull: Yes(1) No(0)
• A will be doing 2unit/day
  B will be 3 and C will be 6.
  Now total work done has to be 60Units ( lcm of 30,20,10)
  
  On day 1 : a +b = 5
  on day 2 : a + c = 8
  Total 13 in 2 days
  No. of Sets : 60/13 = 4.6 approx
  Set of 2, So : 4.6*2 =9.2 Days
• 5 years agoHelpfull: Yes(0) No(1)