a and b working seperatelycan do a piece of workin 9 and 12 days.if they work for a days alternatelywith a begining,the work would be completed in how many days?

• Total work=36(LCM of 12 and 9)
  A=9(4=efficiency)
  B=12(3)
  
  Work. 7×5+1=36
  Days. 2×5+1/4=41/4
• 7 years agoHelpfull: Yes(8) No(0)
• (A+b)'s 2 day's work= 1/9+1/12=36/7
  (A+b)'s 14 day's work= 36/7 * 7=36 ans
• 7 years agoHelpfull: Yes(0) No(3)
• A can complete total work in 9 days.
  One day work of A = 1/9 part.
  B can complete work in 12 days.
  One day work of B = 1/12 part.
  A and B together can complete work in one day,
  = 1/9 + 1/12
  = (4 +3)/36 = 7/36 part.
  Take, 2 days = 1 time unit.
  To time unit needed to complete the work,
  = 1/(7/36) = 36/7 = 5 time unit approx.
  Total Time = 2 *5 = 10 days
• 7 years agoHelpfull: Yes(0) No(1)
• The work will get completed on the 11th day
• 3 years agoHelpfull: Yes(0) No(0)
• Total work done in 2 days = 1/9 + 1/12 = 7/36 -> in 2 days
  So if we multiply 7/36 by 5 we get 35/36
  So the work done till 10th day will be 35/36
  Hence the next day A will come and complete the 1/9 work and it will be 35/36 + 1/9 -> 39/36
  
  Hence the work will get completed in 11th day
• 3 years agoHelpfull: Yes(0) No(0)