Elitmus
Exam
Numerical Ability
Time and Work
a does 20% less work than b.if a can complete a piece of work in 15/2 hours,then b can do it in how many hours?
Read Solution (Total 5)
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- Ratio of percentage of work done by A and B = 80 : 100
Suppose B takes 'x' hours time to complete the work.
So,
⇒ 80 : 100 :: x : 15/2
⇒ 100x = 15/2*80
⇒ x = 600/100
⇒ x = 6 hours (Time taken by B) - 7 years agoHelpfull: Yes(6) No(1)
- a=b-(20/100)*b=4b/5
in 1 hr A does 2/15 work
in 1 hr B does (5/4)*(2/15) work=1/6 work
therefore B takes 6 hrs - 7 years agoHelpfull: Yes(3) No(0)
- 4/5 = b's work time/15/2 or 4/5 = 2(b's work time)/15 => b's work time = 6 hrs
- 7 years agoHelpfull: Yes(1) No(0)
- B=A+A*20%
B=15/2+15/2*20/100
B=9hr - 7 years agoHelpfull: Yes(0) No(6)
- let efficiency of a and b are a and b respectively then a/b=4/5
now a*15/2=5/4a*x
x=6 hours answer - 5 years agoHelpfull: Yes(0) No(0)
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