a is twice as fast as b and b is thrice as fast as c.the journey covered by c in 3/2 hrs will be covered by a in how many minuites?

• let speeds of a,b,c be a,b,c respectively
  given a=2b=6c
  i.e., a will take 1/6 time the c takes
  if c takes 3/2 hrs a will take (1/6)*(3/2)= 1/4 hrs.
• 7 years agoHelpfull: Yes(8) No(0)
• 2a=b =>a=b/2
  3b=c =>b=c/3
  a=c/6
  C=3/2hours
  C=3/2*60=90min
  a=90/6min
  a=15min
• 7 years agoHelpfull: Yes(4) No(0)
• a/b= (2/1)*3
  b/c= 3/1
  a:b:c= 6:2:1
  T= 3/2*x/6x= 1/4 hrs
• 7 years agoHelpfull: Yes(1) No(1)
• given,
  2a=b:3b=c
  c=3/2
  now from 3b=c,
  3b=3/2
  b=3/6=1/2
  now 2a=b
  a=1/2*2=1/4hr
  (1/4)*60=15min
  a=15min
• 7 years agoHelpfull: Yes(1) No(0)
• 15 min. Suppose speed of b be x m/min.
  >implies speed of a is 2x m/min. and that of c be b/3 m/ min.
  Distance=speed x time
  Therefore b travels (x/3(3/2(*60)))=30 x
  Total distance is 30x
  For a ,time = distance/ speed
  > 30x / 2x = 15 min.
• 7 years agoHelpfull: Yes(1) No(0)
• 15 min
  Speed of a=S1
  Speed of b=S2
  Speed of c=S3
  S1=2*S2
  S2=3*S3
  S1=6*S3
  Distance (D) covered by c =S3*3/2 hr
  Then Distance (D) by a =S1*T hr
  S1*T=S3*3/2
  6*S3*T=S3*3/2
  6*T=3/2
  T=1/4 hr or 15 min
• 7 years agoHelpfull: Yes(0) No(0)