a train running at 7/11 of its own speed reached a place in 22 hrs.how much time could be saved if the train would run at its own speed?

• 7/11 of its speed
  so speed 7 : 11
  speed and time inversely proportional to each other
  so time 11 : 7
  time 22 : 14 so 8 hours difference
• 7 years agoHelpfull: Yes(12) No(0)
• distance= speed * time
  let speed of train be "s"
  then distance travelled by speed of (7/11)s in 22 hrs. = (7/11)s *22=14s
  time taken to travel that distance with speed s = 14s/s=14 hrs
  time saved = (22-14)hrs=8hrs
• 7 years agoHelpfull: Yes(6) No(0)
• let speed of train be s=x
  let present speed be s1=7/11(x)
  time =22hrs
  we know that speed=distance/time
  therefore distance=speed * time= 7/11(x) * 22=14x
  now if speed is x then, time=distance/speed=14x/x=14hrs
  so saved time=22-14=8hrs
• 7 years agoHelpfull: Yes(1) No(0)
• If train would run its own speed it could be saved 8 hr.
  By running its own speed train covers the distance in 14 hr.
• 7 years agoHelpfull: Yes(0) No(3)
• Speed is inversely proportional to time.
  So ,
  S1/S2=T2/T1
  7/11=x/2
  X=14 Hr.
  Time saved= 22-14 = 8
• 7 years agoHelpfull: Yes(0) No(0)
• Given speed 7/11 But actual speed (1 - 7/11) = 4/11
  now, Actual speed * time = (4/11 * 22) = 8 hr
• 5 years agoHelpfull: Yes(0) No(0)