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Logical Reasoning
Number Series
how many divisor including 1 but excluding 1000 are there for the number 1000?
Read Solution (Total 13)
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- 1000/2=500
500/2=250
250/2=125
125/5=25
25/5=5
5/5=1
it is 2^3*5^3
for 'n'
n=2^a * 3^b * 5^c * 7^d ..... and so on (primefactorization of 'n')
no. of divisors=(a+1)*(b+1)*c+1).... and so on
for 1000
number of divisors=(3+1)*(3+1)=16(including 1 and 1000)
so, 16-1=15 no. of divisors excluding 1000 - 7 years agoHelpfull: Yes(27) No(0)
- 2^3*2^3 so it have(3+1)*(3+1)=16 including 1 and1000 so acc to q it is 16-1 =15.
- 7 years agoHelpfull: Yes(5) No(2)
- yes we make prime factorization of 1000 so we get as 2*2*2*5*5*5 which can be written as 2^3*5^3;
so we add 1 to both the power and multiply as 3+1*3+1=16 including 1000 so ans is 15 - 7 years agoHelpfull: Yes(3) No(2)
- MANISHA MOHANTY , answer is 15. we have to include 1 also as per question
- 7 years agoHelpfull: Yes(2) No(0)
- Mr.Veerpal could you pls explain it in detail
- 7 years agoHelpfull: Yes(1) No(0)
- in number 1000 is excluding in 15 times because 1000 is division by 2
- 6 years agoHelpfull: Yes(1) No(0)
- 14 total factors are 16 since given excluding 1 and 1000 so it is 14
- 7 years agoHelpfull: Yes(0) No(2)
- 15
1000 factor 2^3*5^3
(3+1)*(3+1)=16 including both 1 and 1000 hence we remove 1000 so ans be 15 - 7 years agoHelpfull: Yes(0) No(0)
- 1000/2 = 500
500/2 = 250
250/2 = 125
125/5 = 25
25/5 = 5
5/5 = 1
2^3*5^3
(3+1)*(3+1) = 16
excluding 1000
16-1 = 15 - 7 years agoHelpfull: Yes(0) No(1)
- no.of divisors of 1000 including 1 and excluding 1000 are 15
- 7 years agoHelpfull: Yes(0) No(0)
- 15 is the answer
- 7 years agoHelpfull: Yes(0) No(0)
- LCM of 1000 is 2*2*5*5*5*2=2^3*5*3
so (3+1)*(3+1)=16
16-1=15
The number of divisors 1000 including 1 and excluding 1000 are 15 - 7 years agoHelpfull: Yes(0) No(0)
- 15
1000=2^3 x 5^3
4*4 =16 factor including 1 & 1000, so excluding 1000 it is 15 - 6 years agoHelpfull: Yes(0) No(0)
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