how many values of x for-

(2x+9)^2/(x+3)

• [(2x+9)^2]/(x+3)= [(2(x+3)+3)^2]/(x+3)
  = [4(x+3)^2+9+2*2(x+3)]/(x+3)
  =4(x+3)^2+12+9/(x+3)
  solving 9/(x+3), x can have 6 possible values:- -2,-4,0,-6,6,-12
• 6 years agoHelpfull: Yes(3) No(0)
• incomplete question.
• 1 year agoHelpfull: Yes(0) No(0)