Number of values of x for -

(2x+9)^2/(x+3)

gives an integral value.

• (2x+9)^2/(x+3)
  ={2*(x+3)+3}^2/x+3
  ={4*(x+3)^2+9+12*(x+3)/(x+3)
  =4*(x+3)+12+9/(x+3)
  to make the whole expression integer we have to make 9/(x+3) an Integer
  so value of x can be -12,-6,-2,0,4,6
  hence number values of x would be 6
• 7 years agoHelpfull: Yes(9) No(1)
• x can have 2 values -1 and -2 so that equation becomes integral.
• 7 years agoHelpfull: Yes(2) No(2)