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A frog is in the bottom of a 20m deep well. Every days it jumps 5 metres upwards and falls 4 metres down. How many dauys will it take for the frog to get out of the well?
16
20
15
19
18
Read Solution (Total 9)
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- 1st day it jumps 5 meters and falls 4 meters, now will be at a height of 1 meter.
2nd day it jumps to 6 meters and falls back to 2 meter.
3rd day it jumps to 7 meters and falls back to 3 meter.
.....
.....
15th day it jumps to 19 meters and falls back to 15 meters.
Finally, 16th day it jumps to 20 meters, but now the frog have reached the top of the well.
Frog reaches top of the well at 16th day. - 7 years agoHelpfull: Yes(12) No(0)
- 16 days.
5-4 = 1 metre upwards per day i.e., 15 metres in 15 days.16 th day it jumps from 15 metres to 20 metres which means it can cross well - 7 years agoHelpfull: Yes(4) No(0)
- 1st day it jumps 5 meters and falls 4 meters, now will be at a height of 1 meter.
2nd day it jumps to 6 meters and falls back to 2 meter.
3rd day it jumps to 7 meters and falls back to 3 meter.
.....
.....
15th day it jumps to 19 meters and falls back to 15 meters.
Finally, 16th day it jumps to 20 meters, but now the frog have reached the top of the well.
Frog reaches top of the well at 16th day. - 7 years agoHelpfull: Yes(1) No(0)
- Because last forwarded frog cannot return in to the well
- 7 years agoHelpfull: Yes(1) No(3)
- 16
coz on 16th day it will have reached the top - 7 years agoHelpfull: Yes(0) No(0)
- total is 20 m. up wards jump 5. and down wards return 4. so5-4=1;
20/1=20; - 7 years agoHelpfull: Yes(0) No(2)
- 20-4=16;
the explanation is in previous of my photo tagged answer - 7 years agoHelpfull: Yes(0) No(3)
- 16
its resultant movement is 1m
So on day 14 he move upto 14m
on day 15 he climbs 19m n dropped to 15m
on day 16 he climbs upto 20 m which is the destination
Congo he has survived :) - 6 years agoHelpfull: Yes(0) No(0)
- 16, Because every day he is taking 1m jump upward and After 15 days whenever he will take jump upward upto 5m he will get out of the wall.
- 5 years agoHelpfull: Yes(0) No(0)
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