7. What is the value of (2a+2b)/(2a-b), given that b ≠ 0 and
(〖 a〗^2-ab+2b^2)/(a^2+ab+4b^2 )=1/3?

A. 4 B. 4/3 C. ¾ D. 3

• 4 . simple calculation
• 7 years agoHelpfull: Yes(2) No(0)
• I think the answer would be 3.
• 7 years agoHelpfull: Yes(0) No(0)
• 4
  As,a=b
• 6 years agoHelpfull: Yes(0) No(0)
• (a^2-ab+2b^2)/(a^2+ab+4b^2)=1/3
  3a^2-3ab+6b^2=a^2+ab+4b^2
  2a^2-4ab+2b^2=0
  (a-b)^=0
  a=b
  
  so
  (2a+2b)/(2a-b)
  2a+2a/2a-a
  4a/a
  4
  
  answer is 4
• 4 years agoHelpfull: Yes(0) No(0)