tickets are numbered from 1,2,,,,1100 and one card is drawn randomly what is the probability of having 2 as a digit

• Numbers which dont have 2 from 1 to 9 = 8
  Numbers which don't have 2 from 10 to 99:
  Let us take two places _ _. Now left most place is fixed in 8 ways. Units place is filled with 9 ways. Total 72 numbers.
  Numbers which don't have 2 from 100 to 999 =_ _ _ = 8 × 9 × 9 = 648
  Numbers which don't have 2 from 1000 to 1099 =10_ _ = 9 × 9 = 81
  Finally 1100 does not have 2. So 1.
  Total number with no 2 in them = 8 + 72 + 648 + 81 + 1= 810
  Tickets with 2 in them = 1100 - 810 = 290
  Required probability = 290 / 1100
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• probability = 1/1100
• 6 years agoHelpfull: Yes(0) No(0)