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Two vessels contain spirit of 0.5 and 0.75
concentrations. If 2 litres from the first vessel and
3 litres from the second vessel are mixed, then
what will be the ratio of the spirit and the water in
the resultant solution
Read Solution (Total 1)
-
- spirit concentration in 2 litre of vessel 1 solution = 2 * 0.5 = 1
spirit concentration in 3 litre of vessel 2 solution = 2 * 0.75 =3.25
ratio = 3.25 : 1.75 = 13 :7 - 6 years agoHelpfull: Yes(0) No(0)
Bank Exam Other Question
tickets are numbered from 1,2,,,,1100 and one card is drawn randomly what is the probability of having 2 as a digit
displaystyle{text{Number of pairs * Sum of each pair} = (frac{n}{2})(n+1) = frac{n(n+1)}{2}}
which is the formula above.
Wait — what about an odd number of items?
Ah, I’m glad you brought it up. What if we are adding up the numbers 1 to 9? We don’t have an even number of items to pair up. Many explanations will just give the explanation above and leave it at that. I won’t.
Let’s add the numbers 1 to 9, but instead of starting from 1, let’s count from 0 instead:
0 1 2 3 4
9 8 7 6 5
By counting from 0, we get an “extra item” (10 in total) so we can have an even number of rows. However, our formula will look a bit different.
Notice that each column has a sum of n (not n+1, like before), since 0 and 9 are grouped. And instead of having exactly n items in 2 rows (for n/2 pairs total), we have n + 1 items in 2 rows (for (n + 1)/2 pairs total). If you plug these numbers in you get:
displaystyle{text{Number of pairs * Sum of each pair} = (frac{n + 1}{2})(n) = frac{n(n+1)}{2}}
which is the same formula as before. It always bugged me that the same formula worked for both odd and even numbers – won’t you get a fraction? Yep, you get the same formula, but for different reasons.
Technique 2: Use Two Rows
The above method works, but you handle odd and even numbers differently. Isn’t there a better way? Yes.
Instead of looping the numbers around, let’s write them in two rows:
1 2 3 4 5 6 7 8 9 10
10 9 8 7 6 5 4 3 2 1
Notice that we have 10 pairs, and each pair adds up to 10+1.
The total of all the numbers above is
displaystyle{text{Total = pairs * size of each pair} = n(n + 1)}
But we only want the sum of one row, not both. So we divide the formula above by 2 and get:
displaystyle{frac{n(n + 1)}{2}}
Now this is cool (as cool as rows of numbers can be). It works for an odd or even number of items the same!