MR D SPENT rs710 in buying 40 copies of three different magazines for his colony club- business india ,business today,business worldpriced at rs 12 rs 25 and rs 15 if the number of copies of business world he bought is heighest among three magazines what is the number of copies of business india and business world together he must have purchased ? option 36 ,26 , 28,30

• x+y+z=40 ..... eq(1)
  12x+25y+15z=710 ..... eq(2)
  
  15*eq1 - eq2 =>
  3x-10y=-110
  
  as 10y and -110 are multiples of 10 so x should be a multiple of 10
  so if x=10,y=14,z=16
  if x=20,y=17,z=3
  as copies of z are more so x=10,y=14,z=16
• 6 years agoHelpfull: Yes(13) No(1)
• answer is 26,
  x+y+z=40
  12x+25y+15z=710,
  on solving and eliminating y term that is business today we get the following equation,
  13x+10z=290,
  now observe the values for x and z such that they satisfy the above equation keeping in mind that z is always greater than the other three, only combination possible is 16 and 10 where z=16 and x=10
  hence answer is 16+10=26
• 6 years agoHelpfull: Yes(2) No(0)
• All options are wrong
• 6 years agoHelpfull: Yes(1) No(1)