If m=(2-√3),then the value of (m^6+m^4+m^2+1) /m^3 is:
A. 64 B. 56 C. 69 D. 52

• after dividing by m^3 ... m^3+m+1/m + 1/m^3 .
  find value of 1/m by rationalizing we get 1/m = 2+root3 also find 1/m^3
  ans b 56
• 6 years agoHelpfull: Yes(6) No(9)
• given, (m⁶ + m⁴ + m² + 1)/m³
  (m⁶/m³ + m⁴/m³ + m²/m³ + 1/m³)
  (m³ + m + 1/m + 1/m³)
  
  now, m = (2 - √3)
  m³ = (26 - 15√3)
  1/m = (2 + √3)
  1/m³ = (26 + 15√3)
  adding (m + 1/m + m³ + 1/m³)
  = (2 - √3 + 2 + √3 + 26 - 15√3 + 26 + 15√3)
  =56
• 5 years agoHelpfull: Yes(3) No(0)
• ((2-root 3)^6+(2-root 3)^4+(2- root 3)^2+1)%(2- root 3)^3=56
• 5 years agoHelpfull: Yes(0) No(0)
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• 4 years agoHelpfull: Yes(0) No(0)