3 cos 80° cosec 10° + 2 cos 59° cosec 31° = ?

• 3 cos80/sin10 + 2cos59/sin31
  3cos80/cos80 + 2cos59/sin59 because>[ sin(90-x)= cosx ]
  =5
• 6 years agoHelpfull: Yes(5) No(0)
• 3cos(90-10) Cosec10+2cos(90-31)cosec(31)
  =3sin10 cosec10+2sin31 cosec31
  =3+2
  =5
• 6 years agoHelpfull: Yes(2) No(0)
• 3(cos80/sin(90-80))+2(cos59/sin(90-59))=3+2=5
• 6 years agoHelpfull: Yes(0) No(0)
• 3 cos 80 cosec 10 + 2 cos 59 cosec 31
  3 cos 80 / sin 10 + 2 cos 59 / sin 31
  3 cos 80 / sin (90 - 80) + 2 cos 59 / sin(90-59)
  3 cos 80 / cos 80 + 2 cos 59 / cos 59
  3 + 2
  5
• 3 years agoHelpfull: Yes(0) No(0)