What is the probability of getting all head in 5 consecutive coin toss?

• 1 case:
  HHHHH
  
  P=(1/2)^5=1/32
• 6 years agoHelpfull: Yes(9) No(0)
• 1/32
  
  Probability of heads 5 times=(1/2)^5=1/32
• 6 years agoHelpfull: Yes(2) No(0)
• 1/(2^5)=1/32
• 6 years agoHelpfull: Yes(1) No(0)
• possibility=2^5=32
  sum of observation (all head ) = (HHHHH) = 1
  probability = sum of observation / possibility
  probability = 1 / 32
• 4 years agoHelpfull: Yes(1) No(0)
• 5c5*(1/2)^0*(1/2)^5
  1/32
• 6 years agoHelpfull: Yes(0) No(0)
• 1/32
  1/2 for each toss, and multiplied together it is 1/32
• 5 years agoHelpfull: Yes(0) No(0)
• 1/120
  If we consider all the possibilities then the total no of possibilities will be 5! i.e. 120 and in only 1 case we got all heads i.e. HHHHH
• 5 years agoHelpfull: Yes(0) No(2)
• Answer=2^5=32
  
  Sum of observations (all heads ) = HHHHH= 1
  probability = sum of observation /total possibility
  so, probability of all heads = 1 / 32
• 1 year agoHelpfull: Yes(0) No(0)
• =1/32
  =Number of Total possible outcomes = 2^5
  =32
  and number of times all heads occur is 1
  hence P = 1/32
• 1 year agoHelpfull: Yes(0) No(0)