In how many ways 7 different people can sit in 4 buses if any people can sit any bus ?

1)7C4
2)7P4
3)7^4

• If we ask all the 7 persons to go and sit in the buses one by one, every person will have 4 choices. He/she can sit in any one of the 4 buses.
  
  So, the number of ways in which one person can sit in which one person can sit in 4 buses = 4.
  
  The same goes for remaining 6 persons.
  
  So, the total number of ways in which 7 persons can sit in 4 buses = 4 (multiplied 7 times) i.e. 4^7.
  
  So, the answer is 4^7.
• 5 years agoHelpfull: Yes(9) No(0)
• Where as given that 7 people can sit in any bus so all of them can sit any one bus also
  so i think 7^4 ways
• 5 years agoHelpfull: Yes(5) No(6)
• Given that a person can sit on any bus.
  This means, the 1st person has 4 buses to choose from AND 2nd person also has 4 buses to choose from AND 3rd person has 4 buses to choose from. ( 4 buses to choose from means there are 4 possible outcomes)
  Just writing the possibilities for 1st, 2nd, 3rd person and so on, we get
  4 AND 4 AND 4 AND.... and so on.
  Remember AND means multiply.
  4 * 4* 4 * 4* 4 * 4 * 4 => 4^7 is right
• 5 years agoHelpfull: Yes(5) No(0)
• The 1st person can go and sit in any of 4 buses so 1st person can sit in 4 ways similarly 2nd person has 4 ways and so on....,therefore 4*4*4*4*4*4*4=4^7 ways
• 5 years agoHelpfull: Yes(3) No(0)
• 7p4
  no explanation needed
• 5 years agoHelpfull: Yes(1) No(5)
• Its belongs to Arrangements so permutation is applicable so and is 7p4
• 5 years agoHelpfull: Yes(1) No(4)
• 7P4 , out of seven people there is four option.
• 5 years agoHelpfull: Yes(0) No(4)
• It's arrangement so it is permutation
  nPr=n!/(n-r)!
• 5 years agoHelpfull: Yes(0) No(4)
• arrrangement 7p4
• 5 years agoHelpfull: Yes(0) No(2)
• permutation nPr=n!/(n--r)!
  7P4
• 5 years agoHelpfull: Yes(0) No(2)
• 3 as it given anyone can sit in any bus
• 5 years agoHelpfull: Yes(0) No(2)
• why not 7p4 we arranging them right??
• 5 years agoHelpfull: Yes(0) No(2)