200meter train travel with the speed of 120kmph and other train travel in opposite direction with speed of 80kmph in 9 seconds. Then find the length of other train ?

1)240
2)300
3)260
4)270

• T=distance/speed
  Distance=L1+L2=200+L2
  Speed=S1 +S2 =120+80=200
  Time=9sec=9*(5/18)=5/2=2.5
  Substitute in above formula we get L2=300m
• 5 years agoHelpfull: Yes(15) No(7)
• Ans: 300m
  
  Opp direction means relative speed=120+80=200kmph (200×5/18)mps
  Time taken to cross each other time=9sec
  First train length lf=200m
  Second train length ls=?
  Time=distance/speed
  9=(200+ls)/(200×5/18)
  
  Solving above you get ls=300m
• 5 years agoHelpfull: Yes(6) No(0)
• 300m
  Relative speed=100/3+200/9=500/9(after converting to m/s)
  let length of other train=x
  than t=d/s
  so t=9s ,d=(200+x).s=500/9 solving it for x you will get 300m
• 5 years agoHelpfull: Yes(2) No(0)
• let length of other train be L
  now ,(200+L)/(120+80)*5/18 =9
  or, 200+L =500
  L=300 meter.
• 5 years agoHelpfull: Yes(2) No(0)
• HeY Manoj kimdly reply i have Wriiten soon pls help
• 5 years agoHelpfull: Yes(1) No(0)
• Relative speed = (120 + 80) km/hr
  
  = 200 x 5/18 m/sec
  = 500/9 m/sec.
  Let the length of the other train be x metres
  Then, (x + 200)/9 = 500/9
  x + 200 = 500
  x = 300.
• 5 years agoHelpfull: Yes(1) No(0)
• 200*5/18*9=500
  First train 200
  So second train 500-200=300
  This process correct or not
• 5 years agoHelpfull: Yes(1) No(0)
• first train is travel at speed 120km/h.
  second at 80km/h
  then the total speed is 120+80 = 200km/h
  time is given in sec. then we change it in hours.
  so we multiply time by18/5 (9*18/5 = 2.5h)
  we know the formula (cross time = total length of train / total speed of train)
  Let we take the length of second train is x.
  2.5 = (200+x)/(120+80)
  2.5(120+80)=200+x
  2.5*200=20+x
  500=200+x
  500-200=x
  300 = x
  so the length of the train is 300 meters
• 5 years agoHelpfull: Yes(1) No(0)
• Relative speed=(120+80)km/hr
  =(200*5/18)m/sec
  =(500/9)m/sec
  Let length of the other train be x
  x+200/9 =500/9
  or, x=300
• 5 years agoHelpfull: Yes(1) No(0)
• 300
  ((200+x)18)/((120+80)5)=9
  then x = 300
• 5 years agoHelpfull: Yes(0) No(0)
• (200+L)/(120+80)*5/18 =9
  or, 200+L =500
  
  L=300 meter which is the length of the other train.
• 5 years agoHelpfull: Yes(0) No(0)
• (200+x)/(100/3+400/18)=300
• 5 years agoHelpfull: Yes(0) No(0)
• 120+80=200kmph
  200*5/18*9=500
  Total length =500
  Length of other train =500-200=300
  Ans :300
• 5 years agoHelpfull: Yes(0) No(0)
• distance=speed*time so................ 200*9=1800*5/18................ to convert KMPH to MTS/SEC multiply with 5/18.................. 1800*5/18=500............... 500-lenght of first train .................... 500-200=300
• 4 years agoHelpfull: Yes(0) No(0)
• length of the train 1 LT=200m
  speed of the 1st train is =120kmph
  Length of the train 2 LT2=?
  Speed of the 2 nd train =80kmph
  Total time T=9sec
  first you will convert the speed kmph to m/sec
  
  First find the Distance of the objects means Relative of the 1st two trains into speed
  
  D=RS*T
  The two train are travel in opposite direction so that the relative speed is equal to the sum of Two speeds are
  D=(120+80)*9
  =200*9*(5/18)
  =500m
  therefore
  Total Distance =LT1 - LT2
  500=200-LT2
  Length of the train LT2=300
• 4 years agoHelpfull: Yes(0) No(0)
• Let the formula for involving two trains is S=(L1+L2)/T. When two trains travel in the opposite direction add the speed and convert it into m/s by multiplying 5/18. so S=(120+80)*5/18 =500/9. Time is clearly given 9 sec. Length of one train L1=200m. so substitute in the formula 500/9=(200+L2)/9 which gives L2 to 300 m.
• 4 years agoHelpfull: Yes(0) No(0)