what is the sum of all 3 digit numbers that can be formed using digits 0,1,2,3,4,5 without repetition

• using this formula (n-1 )!* sum of digits*(11..n)
  5*15*111=8325
• 5 years agoHelpfull: Yes(3) No(1)
• total no. of 3 digits numbers = 5*5*4=100
  the sum of all numbers = 100*(0+1+2+3+4+5)*111= 166500
• 5 years agoHelpfull: Yes(2) No(2)
• by using formula -
  (n-1)! * sum of all the digits * (number of ones depending on the number of digits specified)
  here,
  n=6
  sum of all digits = 1+2+3+4+5 = 15
  number of digits specified is 3, so we'll take 111
  substituting,
  (6-1)! * 15 * (111)
  = 5! * 15 * 111
  = 120 * 15 * 111
  = 199800
• 5 years agoHelpfull: Yes(2) No(0)
• 120
  6*5*4=120
• 5 years agoHelpfull: Yes(0) No(13)
• Total numbers using 5 given no.;
  =>5*5*4=100; for 3 digit no.(o is not taken at 100 place i.e 1st place);
  for one digit no.s sum using given 5 no.=(100/5)=20;
  sum=>20*(0+1+2+3+4+5)*100=30000;
  now for 10th digit place=20*15*10=3000;& 300
  total=30000+3000+300=33300;
• 5 years agoHelpfull: Yes(0) No(5)
• by using formula -
  (n-1)! * sum of all the digits * (number of ones depending on the number of digits specified)
  here,
  n=6
  sum of all digits = 1+2+3+4+5 = 15
  number of digits specified is 3, so we'll take 111
  substituting,
  (6-1)! * 15 * (111)
  = 5! * 15 * 111
  = 120 * 15 * 111
  = 199800
  3 digit no. can not start with zero so
  
  (1,2,3,4,5) sum of all the two digit words
  (5-1)!*(1+2+3+4+5)*11=3960
  
  now the sum is =199800-3960=195840
• 5 years agoHelpfull: Yes(0) No(0)
• 120
  =>6*5*4=120
• 5 years agoHelpfull: Yes(0) No(0)
• We know that zero can't be in hundreds place. But let's assume that our number could start with zero.
  
  The formula to find sum of all numbers in a permutation is
  
  111 * no of ways numbers can be formed for a number at given position * sum of all given digits
  
  No of 1 s depends on number of digits
  
  So,the answer us
  
  111 * 20 *(0+1+2+3+4+5) = 33300
  
  We got 20 as follows..if we have 0 in units place we can form a number in 4*5 ways...this is for all numbers. So we have substituted 20 in formula..hope u understood
  
  Now, this is not the final answer because we have included 0 in hundreds place...so we have to remove the sum of all numbers that starts with 0.
  
  This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5.. because 0 at first place makes it a 2 digit number.
  
  So the sum for this is 11 * 4 * (1+2+3+4+5).
  =660
  
  Hope u understood why we use 4..each number can be formed in 4*1 ways
  
  So, the final answer is 33300-660 = 32640
• 4 years agoHelpfull: Yes(0) No(0)