three dices are thrown what is d probabily to gat atleast one three?

• 91/216
  
  P(getting a 3) = 1/6
  P(not getting a 3 on one throw) = 5/6
  P (not getting a 3 on three throws) = 5/6*5/6*5/6 = 125/216
  
  P(getting at least a 3) = 1- 125/216 = 91/216
• 6 years agoHelpfull: Yes(14) No(5)
• And is 31/216
  To get one 3 = 3,_,_ = 25 possibilities
  To get two 3 = 3,3,_= 5 possibilities
  To get three 3's= 3,3,3= 1 possibilities
  So total 31 possibilities
  
  So probability is 31/216
• 6 years agoHelpfull: Yes(8) No(3)
• 91/216
  p(at least 1 three ) = 1 - p(no three in all three dices)
  p(no three in a dice) = 5/6
  p(no three in all 3 dices) = 5/6 * 5/6 * 5/6
  
  p(at least 1 three ) = 1 - 125/216
  = 91/216
• 6 years agoHelpfull: Yes(3) No(0)