How many terms of the sequence -14, -11, -8,…so on, to make a sum of 1122 ?

• Its an arithmetic progression,
  where first term being -14 and the difference being 3.
  we also have the total sum that is 1122
  therefore by using sum to n terms formula,
  Sn=n/2[2a+(n-1)d]
  1122=n/2[2(-14)+(n-1)3]
  after simplifying we get n=33
• 6 years agoHelpfull: Yes(4) No(1)
• it is in ap
  the sum is already given as 1122
  and the difference is 3
  1122=n/2 *(2(-14)+(n-1)3)
  2244=n(-28+3n-3)
  n=33
• 6 years agoHelpfull: Yes(1) No(2)
• Its in AP:
  so, a=-14
  d=+3
  sum=1122
  then,
  1122=n*(2*a+(n-1)*d)/2
  that gives n=33.
• 6 years agoHelpfull: Yes(0) No(0)
• Given,sum=1122
  let's first no. of the sequence be a and no. of terms of the sequence be n and common difference of the sequence be d
  a=-14
  d=3
  Formula:
  Sum=n/2[2a+(n-1)d]
  n=33 ans.
• 6 years agoHelpfull: Yes(0) No(0)