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Q30. An aircraft takes off from A (89o N Lat, 40o E Long) at 2.00 AM local time to B (32o N Lat, 40o W Long). If the flying time is 11 hours what is the local time of landing at B?
(a) 6.40 AM (b) 4.00 AM (c) 7.40 AM (d) 7.00AM (e) 8.00AM
Read Solution (Total 3)
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- With each degree move time increases by 4 min (since,(24×60min)/360°)=4)
FLIGHT moves 40°E to 40°W so, total degree covered=80°
Means,80°×4=320mins = 5hr20mins
Flight leaves at 2AM +11 hr=1 PM (local time) - 5hr20min delay(as moving east to west countries time is lagging)
=7.40 AM
Ans: 7.40 am - 5 years agoHelpfull: Yes(8) No(1)
- pls can u explain it
- 4 years agoHelpfull: Yes(0) No(0)
- With each degree move time increases by 4 min (since,(24×60min)/360°)=4)
FLIGHT moves 40°E to 40°W so, total degree covered=80°
Means,80°×4=320mins = 5hr20mins
Flight leaves at 2AM +11 hr=1 PM (local time) - 5hr20min delay(as moving east to west countries time is lagging)
=7.40 AM
Ans: 7.40 am - 4 years agoHelpfull: Yes(0) No(0)
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