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What is 28?K=03K(28KC)?K=0283K(K28C) where 28KCK28C is the number of ways of choosing k items from 28 items

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We know that C0+3C1+32C2+…..+3nCn=4n

Substitute n = 28

We get ∑K=0283K(28KC) = 428= 256
6 years agoHelpfull: Yes(2) No(15)

TCS Other Question

There are 26 questions in a test. A student who takes up this test gets 8 marks for a right answer and -5 marks for an incorrect answer, finally he scored 0 marks. How many answers marked are correct? There are 20 persons sitting in a circle. In that, there are
18 men and 2 sisters. How many arrangements are possible,
in which the two sisters are always separated by a man?