navodaya
Exam
Numerical Ability
saina was given some money by her father on her birthday ,saina spent all of it in five shops .In each shop one rupee more than half of what she had when she came in.How much did she get from her father
Read Solution (Total 1)
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- let Saina had x amount
At first shop she spent=x/2+1----------------------(1)
remaining=x-(x/2+1)=x/2-1
at 2nd shop she spent=(x/2-1)/2+1=x/4+1/2--------(2)
reamining=(x/2-1)-(x/4+1/2)=x/4-3/2
at 3rd shop=(x/4-3/2)/2+1=x/8+1/4----------------(3)
remaining=x/4-3/2-(x/8+1/4)=x/8-7/4
at 4th shop=(x/8-7/4)/2+1=x/16+1/8---------------(4)
remaining=x/8-7/4-(x/16+1/8)=x/16-15/8
at 5th shop=(x/16-15/8)/2+1=x/32+1/16-----------(5)
A/Q-she spent all her money at the 5 shops,therefore
(x/2+1)+(x/4+1/2)+(x/8+1/4)+(x/16+1/8)+(x/32+1/16)=x
=>x=62 - 6 years agoHelpfull: Yes(0) No(0)
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