a man travels from his house ti his office at 5 km/hr and reaches his office 20 min late .if his speed had been 7.5 km/hr ,he would have reached his office 12 min early .find the distance from his house to his office.

• 8 km.
  
  Let the distance from house to school be 'x' km, then
  Difference of time taken at two different speeds=20+12=32 min=32/60=8/15 hrs.
  => x/5 - x/(7.5) = 8/15
  => x = 8
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