In a two digit number ,the unit's digit is twice the ten's digit .if 27 is added to the number, the digits interchange their places.the number is

• 36
  
  Let the digits at unit place=x and tens place=y, then the two-digit number=10y+x
  Given, x=2y ---(i) and
  (10y+x)+27 = 10x+y => x -y = -3 ---(ii)
  Solving (i) & (ii), x=6, y=3
  Hence the required number=10y+x=10*3 + 6 = 36
• 6 years agoHelpfull: Yes(0) No(0)