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If (HE)^H=SHE, where the alphabets take the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E)?
Read Solution (Total 14)
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- 25^2 = 625
6+2+5 = 13 - 6 years agoHelpfull: Yes(17) No(2)
- We need to get a three digit number and the last two digits should be equal to the number whose power is taken. Use trial and error method. We know that if we take powers of numbers ending with 5 we should get 5 as the units place digit. Then we can get HE =25 . 25^2=625. so S+H+E = 6+2+5=13.
- 6 years agoHelpfull: Yes(7) No(0)
- please show me ans for its
- 6 years agoHelpfull: Yes(3) No(0)
- Given that we can take value from 0-9
Then most of the possibilities will come
1. If we take H=1 nd E=2 then
(9×2)^2=324
So. 3+2+4= 9 ... - 6 years agoHelpfull: Yes(2) No(12)
- 25^2 =625
6+2+5=13 - 6 years agoHelpfull: Yes(2) No(1)
- Let H=2
(2_)^2 = _2_. The only possibility is E=5
(25)^2 = 625 - 6 years agoHelpfull: Yes(1) No(0)
- (HE)^H=SHE ------> 25^2=625; ( because of H&E values are same in this possibility)
S+H+E ------> 6+2+5=13; (Since the values are S=6 , H=2 , E=5 ) - 6 years agoHelpfull: Yes(1) No(0)
- (25)^2 = 625
So 2+5+6=13 - 6 years agoHelpfull: Yes(1) No(0)
- (6)^2=6x2x3 =>36=36
6+2+3=11 - 6 years agoHelpfull: Yes(1) No(0)
- (HE)^H=SHE
let us assign the value H=2 and E=3
Then, (2*3)^2=36.
Equating by substituting the values of(HE)^H=36'
36=s(2)(3)
value ofs willbe 6.
checking the above equation by substituting the values of SHE=(6)(2)(3)=36
hence the values are S=6,h=2,E=3.
therefore S+H+E=6+2+3=11. - 6 years agoHelpfull: Yes(1) No(2)
- 6+2+5=13
h=2
e=5
s=6 - 6 years agoHelpfull: Yes(1) No(1)
- (HE)^H=SHE
(25)^2=625
so;
H=2; E=5; S=6;
6+2+5=13 - 6 years agoHelpfull: Yes(0) No(0)
- arrange A-J(0-9)
likewise K-L(0-9) and U-Z(0-5)
the code is S=8,H=7,E=4 so 8+7+4=19 or (HE)^H must be in the range 21 to 29 so that result must be less then 999 (3 digit ,as SHE) .
so as per rule sol is (25)^2=625.
so S+H+E=6+2+5=13 ANS - 6 years agoHelpfull: Yes(0) No(0)
- 25*25=625
6+2+5=13 - 6 years agoHelpfull: Yes(0) No(0)
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