In how many ways the word CATHOLICS are arranged such that all that all the vowels should be in odd positions.

• (5p3)*(6!/2!)
• 6 years agoHelpfull: Yes(17) No(1)
• the answer is 43200.
  explanation:- First we have to take nine places because the given word as nine characters and we have to find vowels we have three vowels and five odd places i.e; 5P3*6! = 43200
• 6 years agoHelpfull: Yes(8) No(6)
• according to me,
  no.of consonants are 6(C,T,H,C,L,S)
  no.of vowels are 3(A,O,I)
  first of all arrange all consonants,no.of ways of arranging consanants are 6!/2!(because 2 C's are repeated)
  now arranging 3 vowels in 6 odd places is 6C3*3!
  finally,no.of ways are 6!/2!*6C3*3!
• 6 years agoHelpfull: Yes(4) No(3)
• total no. of vowels=3
  total no. of consonants = 6
  and total odd position =5(1,3,5,7,9)
  so,vowels are arranged in =5C3*3! ways
  so,result is
  5C3*6!*3!=43200
• 6 years agoHelpfull: Yes(3) No(3)
• no.of consonants are 6(C,T,H,C,L,S)
  no.of vowels are 3(A, O, I)
  no.of odd places are 5
  first of all, arrange all consonants,no.of ways of arranging consonants are 6!/2! (because 2 C's are repeated)
  now arranging 3 vowels in 5 odd places is 5C3*3!
  finally,no.of ways are 6!/2!*5C3*3!=21600
• 5 years agoHelpfull: Yes(3) No(0)
• Answer:
  
  21600
  
  Step-by-step explanation:
  
  CATHOLICS
  
  Vowels - A O I
  
  Consonant - C , T , H , L S C
  
  Odd positions 1 , 3 , 5 , 7 , 9 = 5 Posistions
  
  all the vowels
  
  3 Vowels can be positioned
  
  in ⁵P₃ = 5!/(5-3)! = 5!/2! = 60
  
  Remaining positions
  
  9 - 3 = 6
  
  6 Positions can be filled
  
  in 6!/ 2! ways as C is repeated
  
  = 360
  
  Total = 360 * 60
  
  = 21600
• 3 years agoHelpfull: Yes(1) No(0)
• 3 vowels can be arranged in 5 odd places i.e; 5C3=10
  6 consonants can be arranged in 4C6 ways i.e; 6
  Total is 6*10=60
• 6 years agoHelpfull: Yes(0) No(1)
• there are 3 vowels.so the number of ways they can be arranged in 5C3.
  the remaining can be arranged in 6! ways.
  therefore, total ways are 6!*5C3
• 6 years agoHelpfull: Yes(0) No(0)
• Total number of places are:9
  odd places are :5
  Vowels are: a,o, i =3.
  So we can place 3 vowels in any 5 places=5p3=20
  After you placed 3 vowels they are 6 places are empty yet and we need to place all 6 consonants.
  So 6p6=720.
  Total=20*720=14800
• 6 years agoHelpfull: Yes(0) No(1)
• The answer is 43200.
  We had put all the vowels in one box and to arrange all this three vowels no of ways is 3! .
  There are 9 places were present and to arrange all the letters no of ways is 6! Because we have remove 3 three. So the total letter will be 6.
  Finally:-6! ×3! =43200
• 5 years agoHelpfull: Yes(0) No(0)
• 5c3*5!=7200
• 5 years agoHelpfull: Yes(0) No(1)
• the answer is 7200
• 5 years agoHelpfull: Yes(0) No(0)
• 3 vowels can be placed in 5 places in 5p3 ways and 6 consonents in 6 places in 6! Ways
  Ans:5p3×6!
  =60*120
  = 43200
• 4 years agoHelpfull: Yes(0) No(2)
• 5p3*(6!/2!)
• 2 Months agoHelpfull: Yes(0) No(0)