to obtain 23 liters of a production line solution that contains 10% of chemical A , sample of a solution containing 13% of chemical A and another containing 3 % of chemical A are to be mixed. how many liters of 13% sample are required a)76.67 b)6.9 c)16.1 d)6.19 e)19.58

• we can use alligations and mixturs concept here
  
  13% 3%
  10%
  7% 3%
  
  now total 10% contain 23lit
  7%------------?
  7*23/10=16.1
• 6 years agoHelpfull: Yes(7) No(0)
• let x be amount of solution containing 13% of chem A. Make a table to find the totals:
  
  Solution Amount Decimal Total
  ------------------------------------------------------------
  3% 23 - x .03 .03*(23-x)
  
  13% x .13 .13 * x
  
  10% 23 .1 .1 * 23
  
  The total of the 3% solution plus the total of the 13% solution must equal the total of the 10% solution.
  
  0.69-0.03x + 0.13x = 2.3
  0.1x=1.61
  x = 16.1 Answer C
• 6 years agoHelpfull: Yes(1) No(1)
• 13 3
  10
  7 3
  
  7x+3x=23
  x=2.3
  13% sample so,
  7x=7*2.3=16.1
• 6 years agoHelpfull: Yes(1) No(0)