two administrative assistants were typing a 135 page report if one admin assistant typed one and 5/10 times as many pages as the other, how many pages did the more rapid admin assistant type?

• 27 pages
  
  Let slower assistant types 'x' pages, then faster one types x*(1 & 5/10) = x*15/10 = 3x/2 pages.
  So ratio of their pages typed = x : 3x/2 = 2 : 3
  Therefore in total 135 pages, slower assistant types 135*(2/5)=54 pages and faster 81 pages.
  Hence faster assistant typed 81 - 54 = 27 more pages.
• 6 years agoHelpfull: Yes(13) No(7)
• 1&5/10*x + x = 135
  15*x/10 + x = 135
  x = 54
  radip admin typed = 15*x/10 = 15*54/10 = 81 pages
• 6 years agoHelpfull: Yes(8) No(3)
• As it is given in question that :-
  rapid=1.5*slower;
  so, the ratio become rapid/slower=3/2;
  therefor in total 135 pages,slower assistant type 135*(2/5)=54pages and rapid type 81 pages.
  hence faster assistant typed 81-54=27 more pages.
• 5 years agoHelpfull: Yes(1) No(1)
• assistant a does x pages and assistant b does x + 5/10x pages.
  
  x+(5/10x) = x + 1/2x = 2 1/2x = 2.5x = 135pages total.
  
  
  x = 135/2.5 = 54pages
  
  assistant a does x.....54 pages
  assistant b does x+5/10x.......54 + 27 = 81 pages
  
  81 - 54 = 27 pages more done by assistant b
• 5 years agoHelpfull: Yes(0) No(1)
• let x+y=135
  x=1*5/10y
  so 1*5/10+y=135
  then y=54
  and x=81
  difference is the more rapid papges typed=81-54=27;
• 5 years agoHelpfull: Yes(0) No(0)