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Numerical Ability
Time and Work
A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start
the work together but C leaves 4 days before the completion of the work. In how
many days is the work done?
Read Solution (Total 1)
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- ne day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.
C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.
Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.
Remaining Work = 7/10, which was done by A,B and C in the initial number of days.
Number of days required for this initial work = 7 days.
Thus, the total numbers of days required = 4 + 7 = 11 days. - 6 years agoHelpfull: Yes(0) No(0)
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