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Numerical Ability
Permutation and Combination
A student is to answer 9 out of 12 questions in an examination such that he must choose at least 5 from the first six questions. The number of choices available to him is
Read Solution (Total 3)
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- =6C5*6C4+6C6+6C3
=90 + 20
=110 - 5 years agoHelpfull: Yes(2) No(0)
- =6C5*6C4+6C6+6C3
=50 - 5 years agoHelpfull: Yes(0) No(3)
- 6C5*6C4+6C6*6C3
45+20
65 - 5 years agoHelpfull: Yes(0) No(0)
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