A train running at 8/11 of its original speed reached a place in 27 hours 30 minutes. How much time could be saved if the train would have run at its original speed?

• Let 'x' be the Original Speed
  Given Speed =8/11(Original Speed)
  As Speed Is Inversely Proportional to Time
  11/8(x)=55/2
  x=55/2*8/11
  x(original Speed)=20 hrs.
  If he runs with Original Speed then Saved Time= 55/2 -20
  = 7.5hrs
• 5 years agoHelpfull: Yes(3) No(0)
• Let the speed of the train be x.
  Then 8x/11 + x = 27.5 => x = 16 hours.
  Therefore it could save 11 hours 30 minutes of the train had run at its original speed .
• 6 years agoHelpfull: Yes(0) No(5)