A 70 foot pole stands vertically in a horizontal plane supported by three 490 foot wires, all attached to the top of the pole. Pulled and anchored to three equally spaced points in the plane. How many feet apart are any two of those anchor points?

• Find the radius formed by the distance between the pole and the wire:
  
  The radius, the pole and the wire formed a right angle triangle
  
  a² + b² = c²
  
  70² + radius² = 490²
  
  4900 + radius² = 240100
  
  radius² = 240100 - 4900
  
  radius² = 235200
  
  radius = 484.97 ft
  
  Find the circumference formed by the anchor points:
  
  Circumference = 2πr
  
  Circumference = 2π(484.97) = 3048.41 ft
  
  Find the distance between two anchors:
  
  Distance between 2 anchors = 3048.41 ÷ 3 = 1016.14 ft
  
  Answer: The distance between two anchors is 1016.14 ft
• 5 years agoHelpfull: Yes(17) No(4)
• answer is 149.61.....
• 5 years agoHelpfull: Yes(3) No(9)
• the anchor points of wire are equally spaced around a circle of radius r,
  r=sq.rt(490^2-70^2)=280 sq.rt(3) ft
  line between two anchor points is a chord that subtends a central angle of
  teta=(2*pi)/3
  chord length=2r*sin(teta/2)=840 ft
• 5 years agoHelpfull: Yes(3) No(6)