Father is aged three times more than his son Roy. After 8 years, he would be two and a half times of Roy's age. After further 8 years, how many times would he be of Roy's age?

• First clearly understand the question..the question expects "how many times the father's age would be of his son roy's age"..
  let F=father S=son
  condition 1- F=3S
  condition 2- F+8=2.5(S+8)
  substitute condition 1 in condition 2
  we get 3S+8=2.5S+20
  after derivation we get F=72 , S=24
  Then the expected value is F's age in multiples of S's
  then simply derive the values after 16 years (8+8)
  then father age would be 88 years and son's age would be 40 years
  
  Now divide father's age by son's age we get 88/40=2.2
  thus father's age is 2.2 times of son's age after 16 years (8+8)
• 6 years agoHelpfull: Yes(26) No(1)
• let son present age=x
  fatger=3x
  after 8yrs
  3x+8=2.5(x+8)
  x=24 son age
  father=72
  after further 8 yrs i.e. 16 yrs fathers age =72+16=88
• 6 years agoHelpfull: Yes(21) No(14)
• let son present age=x
  fatger=3x
  after 8yrs
  3x+8=2.5(x+8)
  x=24 son age
  father=72
  after further 8 yrs i.e. 16 yrs fathers age =72+16=88
  after further 8 yrs i.e. 16 yrs son age =24+16=40
  father age would be 40/88 times than roy's age.
  i.e. 5/11 (Ans)
• 6 years agoHelpfull: Yes(10) No(1)
• First clearly understand the question..the question expects "how many times the father's age would be of his son roy's age"..
  let F=father S=son
  condition 1- F=3S
  condition 2- F+8=2.5(S+8)
  substitute condition 1 in condition 2
  we get 3S+8=2.5S+20
  after derivation we get F=72 , S=24
  Then the expected value is F's age in multiples of S's
  then simply derive the values after 16 years (8+8)
  then father age would be 88 years and son's age would be 40 years
  
  Now divide father's age by son's age we get 88/40=2.2
  thus father's age is 2.2 times of son's age after 16 years (8+8)
  THIS IS CORRECT
• 5 years agoHelpfull: Yes(5) No(0)
• let Roy's age be x
  so father's age=3x
  now as per ques
  2.5x when x+8
  so .5x =8
  x=16
  when roy 32 father will be 48+16=64 which is twice
• 6 years agoHelpfull: Yes(4) No(5)
• Father Roy
  3x+x=4x ----------------------- ----- x
  (5(x+8)/2)=4x+8 ----------------------- x+8
  x=8
  
  so after further 8 years
  roy=8+8+8=24
  father=(4*8)+8+8=48
  so father is two times of roy
• 6 years agoHelpfull: Yes(3) No(1)
• Roy father
  x 3x - - - - present
  x+8 5/2(x+8) - - - - after 8 years
  So,
  3x+8 = 5/2(x+8)
  Solve,
  x=24.
• 6 years agoHelpfull: Yes(2) No(1)
• Let's consider current age of father and Roy is f,r.
  F is three times more than Roy.
  F=3R -------(1)
  After 8 years, he would be two and a half times of Roy's age.
  F+8=2+1/2(R+8)
  F+8=5/2(R+8) ---------(2)
  Supstitute (1) in (2)
  3R+8=5/2(R+8)
  6R+16=54+40
  R=24,F=72.
  Initially 8 years after and further after 8 years totally 16 years.
  So, R+16,F+16
  R=40 ,F=88.
  So totally 88/40=2.2
  2.2 times would be Roy's age
• 5 years agoHelpfull: Yes(2) No(0)
• son present age=x and father=3x
  After 8years son edges=x+8 and father edges=x+8
  =>3x+8=5/2(x+8)
  =x=24 son age
  father=72
  after further 8 yrs i.e. 16 yrs fathers age =72+16=88
• 5 years agoHelpfull: Yes(1) No(1)
• let age of Roy is x and father will be 3x.
  after 8 years age of Roy will be x+8 and father is 2.5(x+8).
  so, 3x-2.5(x+8)=8 => x=24.
  Roy is 24 years and father is 72.
  After further 8 years Roy is 40 and father is 88.
  i.e, 2.2 times of Roy's age.
• 5 years agoHelpfull: Yes(1) No(0)
• Present age of Son=S yrs
  Present Age of father=F yrs.
  Now, F=3S ......(1)
  and F+8=2.5(S+8).....(2)
  Solving, S=24 and F=72 Yrs.
  Adding 16 yrs, F+16/S+16= 88/40= 2.2.
  
  Correct Answer:2.2
• 5 years agoHelpfull: Yes(1) No(0)
• let roy age be R
  and father's age be F
  then // father age is three times roy age //
  so F=3R ----------(1)
  
  NOW , // after 8 years //
  father age = F+8
  roy age = R+8
  
  AND father is 5/2 times of roy age
  so (F+8) = 2.5 (R+8) --------- (2)
  
  from eqn (1) and (2)
  we get
  F = 72 years and R= 24 years
  
  // further 8 years //
  father age is F = 80 years
  and
  roy age be R= 32 years
  
  so father is [ 80/32 times = 5/2 times] or 2.5 times be of Roys age
• 4 years agoHelpfull: Yes(1) No(0)
• Son=x
  Father=3x+x=4x
  After 8 yrs..
  4x+8=5/2(x+8)
  8x+16= 5x+40
  3x=24
  X=8
  Now son age= x+8=16
  Father age=4x+8=32+8=48
  
  As asked in the que. After further 8 yrs so..
  Sons age=16+8=24
  
  So father would be 2 times the age of his son
• 4 years agoHelpfull: Yes(1) No(0)
• Thanks all for your help!!
• 6 years agoHelpfull: Yes(0) No(1)
• Assume that, present age of Roy be x.
  Father age will be 3x.
  After 8 years Roy age will be x+8 and father age will be 2.5(x+8).
  There fore 3x-2.5(x+8)=8 => x=24.
  Father age will be 72 and after 8 years he will be 80.
  After further 8 more years he will be 88 and Roy will be 40.
  i.e, father is 2.2 times of Roy's age
• 5 years agoHelpfull: Yes(0) No(0)
• let son present age=x
  f-s=3x=>f=4x
  f+8=5/2(s+8)
  2f=5s+24
  8x=5x+24
  3x=24
  x=8
  f=4*8=32
  after 16 years f=48,s=24
  f:s=2:1
• 5 years agoHelpfull: Yes(0) No(0)
• Roy age =x;
  father age=3x;
  
  After 8 year 3x+8= 5/2(x+8);
  solve this we get x=24;
  now after further 8 years roy is 40and father is 88
  which is 11/5 times (88= 11/5(4));
  answer is 11/5
• 5 years agoHelpfull: Yes(0) No(0)
• F=3R
  After 8 yr, F+8=(R+8)*2and1/2
  =(R+8)*5/2
  By this R=24,and F=72
  After 16 year, R will (24+16)=40
  F will (72+16)=88
  88/40=2.2 times
• 4 years agoHelpfull: Yes(0) No(0)
• father=f, son=s
  father befor 8 year =3x
  son befor 8 years=x
  father now = 3x+8
  son now= x+8
  
  2.5(x+8) = 3x+8
  x= 24
  there for fathers age after 8 year =88
  son age after 8 year = 40
  so ratio is 40/88=2.2
• 3 years agoHelpfull: Yes(0) No(0)
• let Roy age is 'x' years.so his father's age is 3x.
  after 8 years,
  therefore,roy age is 'x+8' his fathers age is 2 and half times ronit age
  so
  3x+8=5/2(x+8)
  ..x=24 fathers age =3(24)=72
  after 8 years ronit age=32 and fathers age is 80
  again after 8 years ronit age=40 and fathers age is 88
  therefore fathers age is 2.2 times of ronit age.
• 3 years agoHelpfull: Yes(0) No(0)