A trader had 1200 kg of wheat.He sold a part of it at 5% profit and rest at 11 % profit so that he made a total profit of 7%.How much wheat did he sell at 5% profit?

• x*105+(1200-x)*111=1200*107
  or,x=800
• 5 years agoHelpfull: Yes(13) No(1)
• Total Wheat = 1200Kg
  one part is sold at = 5% profit
  other part is sold at = 11% profit. So the total profit is 7% of 1200=Rs 84
  so we have two parts in 1200 kg
  split 1200 into 800 kg and 400 kg
  first part is sold at 5% , so 5% of 800 = Rs 40
  second part is sold at 11% , so 11% of 400 = Rs 44
  first part + second part = Rs 40 + Rs 44
  = Rs 84,which is equal to total profit
  Therefore 800 Kg of wheat is sold at 5%profit
• 5 years agoHelpfull: Yes(8) No(7)
• Let total cost price be 1200.
  Let Part of it be x....and given that paert of it is sold at 5% profit so.....selling price=(105/100)*x
  Remaining part be 1200-x.... and it is sold at 11% profit....selling price=(111/100)*1200-x
  Total 1200kg is sold at 7% profit....so selling price is (107/100)*1200
  so total.....=,
  ((105/100)*x)+((111/100)*1200-x)=(107/100)*1200
  by solving this we get 800kg.
• 5 years agoHelpfull: Yes(5) No(1)
• 5% 11%
  
  7%
  4 : 2
  2. : 1
  2/3×1200=800
  Using mixture and allegations
• 5 years agoHelpfull: Yes(3) No(1)
• by allegation and mixtures
  
  5 11
  
  
  7
  4 2
  
  
  
  2 : 1 is the ratio
  so
  2/3 * 1200 = 800
• 5 years agoHelpfull: Yes(1) No(0)
• 5. 11. (write both profits together)
  7. (Write overall profit)
  4. 2. (Cross sub 11-7 and 5-2)
  =2:1
  2/3*1200=800kg.
• 4 years agoHelpfull: Yes(1) No(0)
• 800kg solved by butterfly method
• 5 years agoHelpfull: Yes(0) No(1)
• x/(1200-x)=(11-7)/(7-5).......................find for x
• 5 years agoHelpfull: Yes(0) No(1)