A man buys 24 litres of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 10 litres of another mixture with 30% of liquid. What is the percentage of water in the new mixture?

• % of Liquid in Solution A = 25%
  
  ⇒ % of Water in Solution A = 75%
  
  Volume of Solution A = 24 Litres
  
  ⇒ Volume of Water in Solution A = (75/100) × 24 = 18 Litres
  
  % of Liquid in Solution B = 30%
  
  ⇒ % of Water in Solution A = 70%
  
  Volume of Solution B = 10 Litres
  
  ⇒ Volume of Water in Solution B = (70/100) × 10 = 7 Litres
  
  If Solution A is mixed with Solution B
  ⇒ Net Total Volume of Solution = (24 + 10) = 34 Ltrs
  
  ⇒ Net Total Volume of Water in Solution = (18+ 7) = 25Ltrs
  
  % of Water in New Mixture = (Volume of Water in New Mixture / Volume of New Mixture) × 100
  
  % of Water in New Mixture = (25 /34) × 100 = 73.52%
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