If log 27 = 1.431, then the value of log 9 is: (A) 0.934 (B) 0.945 (C) 0.954 (D) 0.958

• log27=1.431
  log3^3=1.431
  3log3=1.431
  log3=1.431/3
  log3=0.477
  log9=log3^2 then
  2log3
  2*0.477 = 0.954
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• Ans C (0.954)
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• log 27 = 1.431
  log(33) = 1.431
  3 log 3 = 1.431
  log 3 = 0.477
  log 9 = log(32)= 2 log 3 = (2 x 0.477) = 0.954
• 5 years agoHelpfull: Yes(4) No(0)
• log 27 = 1.431
  log(33) = 1.431
  3 log 3 = 1.431
  log 3 = 0.477
  log 9 = log(32)= 2 log 3 = (2 x 0.477) = 0.954
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• log27= log3~3= 3log3=1.431
  So, log9= 2log3= 2*(1.431/3)=0.954
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• log 27=log 3^3 =3 log 3.......
  log 9= log 3^2=2 log 3..2*0.477=0.954
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• log(3^3)=1.431
  3log3=1.431
  log3=0.477
  log9=2*log3=2*0.477=0.954
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• log3^3=1.431
  3log3=1.431
  log3=(1.431/3)
  
  log9=log3^2=2log3=2*(1.431/3)=0.954
  So answer is C
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• 3 log3=1.431 ==>log3=1.431/3
  log9=2log3=2*(1.431/3)=2*0.477=0.954
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• log 9=log 3^2 =2(log 3)=2(0.477)=0.954
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• log9
  log(3)^2
  2log3 = 0.954
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• 3 log 3=1.431
  log 3=1.431/3
  log 3=0.477
  2 log 3= 2*0.477=0.954
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• log27=1.431 log9=?
  log(3^3)=1.431 log(3^2)=2log3
  3log3=1.431 =2*0.477
  log3=0.477 =0.954
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• Ans is 0.954
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• 3log3=1.431
  log3=1.431/3
  2log3=2*log3=0.954
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• 2 ×0.477=0.954
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• log 0(27) = 1.431
  log (3^3) = 1.431
  3 log3 = 1.431
  log3 = 0.477
  log9 = log(3^2) = 2 log3
  2 log3 = 2*0.477
  = 0.954
  
  Ans: C
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