IBM
Company
Numerical Ability
Log and Antilog
If log 27 = 1.431, then the value of log 9 is: (A) 0.934 (B) 0.945 (C) 0.954 (D) 0.958
Read Solution (Total 18)
-
- log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log9=log3^2 then
2log3
2*0.477 = 0.954 - 5 years agoHelpfull: Yes(6) No(0)
- Ans C (0.954)
- 6 years agoHelpfull: Yes(4) No(1)
- log 27 = 1.431
log(33) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32)= 2 log 3 = (2 x 0.477) = 0.954 - 6 years agoHelpfull: Yes(4) No(0)
- log 27 = 1.431
log(33) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32)= 2 log 3 = (2 x 0.477) = 0.954 - 6 years agoHelpfull: Yes(1) No(1)
- log27= log3~3= 3log3=1.431
So, log9= 2log3= 2*(1.431/3)=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- log 27=log 3^3 =3 log 3.......
log 9= log 3^2=2 log 3..2*0.477=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- log(3^3)=1.431
3log3=1.431
log3=0.477
log9=2*log3=2*0.477=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- log3^3=1.431
3log3=1.431
log3=(1.431/3)
log9=log3^2=2log3=2*(1.431/3)=0.954
So answer is C - 5 years agoHelpfull: Yes(0) No(0)
- 3 log3=1.431 ==>log3=1.431/3
log9=2log3=2*(1.431/3)=2*0.477=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- Please send me vudathabhavishya@gmail.com
- 5 years agoHelpfull: Yes(0) No(0)
- log 9=log 3^2 =2(log 3)=2(0.477)=0.954
- 5 years agoHelpfull: Yes(0) No(0)
- log9
log(3)^2
2log3 = 0.954 - 5 years agoHelpfull: Yes(0) No(0)
- 3 log 3=1.431
log 3=1.431/3
log 3=0.477
2 log 3= 2*0.477=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- log27=1.431 log9=?
log(3^3)=1.431 log(3^2)=2log3
3log3=1.431 =2*0.477
log3=0.477 =0.954 - 5 years agoHelpfull: Yes(0) No(0)
- Ans is 0.954
- 5 years agoHelpfull: Yes(0) No(0)
- 3log3=1.431
log3=1.431/3
2log3=2*log3=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- 2 ×0.477=0.954
- 5 years agoHelpfull: Yes(0) No(0)
- log 0(27) = 1.431
log (3^3) = 1.431
3 log3 = 1.431
log3 = 0.477
log9 = log(3^2) = 2 log3
2 log3 = 2*0.477
= 0.954
Ans: C - 5 years agoHelpfull: Yes(0) No(0)
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