We have two cubes. the sum of the two cubes is 25. The sum of a side length of one cube and a side length of the other is 4. What is the sum of the total surface areas of the two cubes?

• Let a side of one cube be X and one side of another cube be Y.
  Given X+Y=4
  Surface area of cube = 6s^2
  6X^2 = 6Y^2 by sloving we get Y=2 [ since X=4-Y]
  We also get X=2
  The sum of total surface areas of the two cubes = 48
• 5 years agoHelpfull: Yes(0) No(2)
• 'a' is the side of one cube and 'b' is the side of another one.
  Sum of Vol of two cubes (a^3+b^3) =25.
  Sum of sides of two cubes (a+b) =4.
  (a+b)^3= a^3 + b^3 + 3ab(a+b).
  From above eqn we got, ab =(39/12).
  Then w.k.t (a+b) ^2= a^2 + b^2 +2*ab.
  Substitute ab =(39/12) and (a+b) =4 as we know.
  Finally we got (a^2 + b^2) value. - - - eqn 1
  Surface area of cube is 6*(a^2 + b^2).
  Put eqn 1 in above so that we get 48.
  Thank you...
• 5 years agoHelpfull: Yes(0) No(2)