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Sunil starts from home at 4 pm and reaches school every day at 5 pm to pick up his children.on Saturday
the school got over at4 pm and children started walking towards home. Sunil met them on the way and returned home 15min early. if the speed of Sunil is 35km/hr then for how many mins did children walk? what is the speed of children?
Read Solution (Total 10)
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- children's walk-52.5min distance travelled by children-4.37 therefore, speed=4.37*60/52.5=5km/hr
- 5 years agoHelpfull: Yes(4) No(4)
- speed of sunil is 35km/hr. so that school is 35/2= 17.5 KM away from Home.
Sunil reaches 15 mins early so distance travelled by sunil : 35*45/60= 26.25KM
sunil travels towards school= 26.25/2 = 13.125KM
students travelled= 17.5-13.125= 4.375 KM
Time taken by sunil to travel one side = 45/2= 22.5 Mins.
so students walk 22.5 Mins.
speed of students = 4.375/(22.5/60)= 11.66 KM/Hr. - 5 years agoHelpfull: Yes(2) No(1)
- Distance between home and school is 17.5km
Sunil travels for 45 min or after 22.5 min he picks his child
So child also walked for 22.5 min as both started a 4pm
Sunil travels = 35 x 22.5/60 = 105/8 km = 13.125 km towards school
Child travels = 17.5 - 13.125 = 4.375 km
Speed of Child = 4.375/(22.5/60) = km = 11.66 km/hr - 4 years agoHelpfull: Yes(1) No(0)
- I will give you correct answers with solution
distance from home to school-->35km
speed of sunil-->35km/hr
sunils total time for pick up children in normal days-->2hrs
sunils total time for pick up children in the saturday-->1hrs 45 minutes
Thus he saved 15 min travel, equivalent to the up and down time taken by sunil to travel between the specific point and the school.
So the distance travel by children=distance between the point and the school=speed of sunil * time saved /2 (time in minutes is converted to hours)
=35*0.125=4.375km
Now, Sunil time taken by sunil to reach the children=time traveled by children from school to the specific point
thus (time taken by sunil to reach school)-(time saved in one direction) i.e., 60-7.5=52.5 min
Now calculating speed of the children speed of children= distance trav. by children/time taken in hours
=4.375/(52.5/60)=5km/hr
Thus answers are
Children walked time=52.5min
Speed of children=5km/hr
The answers given before didn't understand question correctly.. - 4 years agoHelpfull: Yes(1) No(0)
- 52.5min he walked
- 5 years agoHelpfull: Yes(0) No(12)
- how?? 52.5 min ,can u explain ?
- 5 years agoHelpfull: Yes(0) No(3)
- As they arrived 15 minutes earlier than usual, they saved 15 minutes on round trip from home to school (home-school-home) --> 7.5 minutes in each direction (home-school) --> children meets Sunil 15 minutes earlier the usual meeting time --> children arrived an hour earlier i.e at 4 pm than the usual meeting time, so children must have spent walking the rest of the time before their meeting, which is hour-7.5 minutes=52.5 minutes.
- 5 years agoHelpfull: Yes(0) No(8)
- 15 min children walked and speed = 1.4625km/hr
- 5 years agoHelpfull: Yes(0) No(2)
- 7.5 mins children walked
distance 625m @ 5KM/hr - 4 years agoHelpfull: Yes(0) No(0)
- I will give you correct answers with solution
distance from home to school-->35km
speed of sunil-->35km/hr
sunils total time for pick up children in normal days-->2hrs
sunils total time for pick up children in the saturday-->1hrs 45 minutes
Thus he saved 15 min travel, equivalent to the up and down time taken by sunil to travel between the specific point and the school.
So the distance travel by children=distance between the point and the school=speed of sunil * time saved /2 (time in minutes is converted to hours)
=35*0.125=4.375km
Now, Sunil time taken by sunil to reach the children=time traveled by children from school to the specific point
thus (time taken by sunil to reach school)-(time saved in one direction) i.e., 60-7.5=52.5 min
Now calculating speed of the children speed of children= distance trav. by children/time taken in hours
=4.375/(52.5/60)=5km/hr
Thus answers are
Children walked time=52.5min
Speed of children=5km/hr
The answers given before didn't understand question correctly.. - 4 years agoHelpfull: Yes(0) No(0)
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