Write numbers from 100 to 365 in a sequence like 100101102103104105... 364365. How many
times the digit 9 occurs in the sequence?

• 100 to 200 - 20,
  200 to 300 - 20,
  300 to 365 -6
  20+20+6=46.
  ans 46
• 5 years agoHelpfull: Yes(7) No(0)
• starting from 100 count the 9's occurred like 109,119,129...upto 199. In 199 we get 2 9's and fromm 190 to 198 we get nine 9's. Do it upto 200 we get 40 9's. Finally from 300 to 365 count 309,319,329,339,349,359.
  Add these 20+20+6 = 46 is the final answer
• 5 years agoHelpfull: Yes(4) No(2)
• 24 times it happen.. because it comes this times
• 4 years agoHelpfull: Yes(1) No(0)
• 100 to 200- 20
  200 to 300-20
  300 to 400-6
• 5 years agoHelpfull: Yes(0) No(0)
• 100 to 190=10 and 191 to 199 =10
  200 to 290 =10 and 291 to 299=10
  300 to 365 =6
  10+10+10+10+6=46
• 4 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int n,i,j,k=0;
  for(i=100;i0;j/=10)
  {
  if(j%10==9)
  k++;
  }
  }
  printf("%d",k);
  }
• 4 years agoHelpfull: Yes(0) No(1)
• 26
  
  100 to 199 9 occurs 11 times
  209 to 299 as well 9 occurs 11 times
  from 309 to 359 4 times 9 will be there
  So 11 + 11 + 4 = 26
• 2 years agoHelpfull: Yes(0) No(1)
• Sorry the answer is 46 not 26
• 2 years agoHelpfull: Yes(0) No(0)