IBM
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Numerical Ability
Log and Antilog
If log 27 = 1.431, then the value of log 9 is:
A. 0.934
B. 0.945
C. 0.954
D. 0.958
Read Solution (Total 10)
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- C. 0.954
log 27 = 1.431
log(3³) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(3²)= 2 log 3 = (2 x 0.477) = 0.954 - 5 years agoHelpfull: Yes(10) No(0)
- C. Because. Log+Log9 =1.431
- 5 years agoHelpfull: Yes(1) No(0)
- log 27 = 1.431
log (3) ^ (3) = 1.431
3 log 3 = 1.431
Multiply and divide by 2
(3*2 log 3) / 2 = 1.431
3 log 9 = 2.862
log 9 = 0.954 - 5 years agoHelpfull: Yes(0) No(0)
- 0.954
Log 27=1.431
Log(3*3*3) =1.431
Log 9+log 3=1.431
Log 3^3=1.431
3 log 3=1.431
Log 3=0.477
Log 9=log3^2=2log3=0.477*2=0.954 - 5 years agoHelpfull: Yes(0) No(0)
- log(3)^3=1.431
log3=0.477
log 9 = log 3 + log 3
log 9 = 0.954 - 5 years agoHelpfull: Yes(0) No(0)
- 3 log 3=1.431
log 3=1.431/3=0.477
log 3*3=0.954 (0.477*2) (square one side then we can multiply with another side)
like
log 2=0.30129
log 2*2=0.30129*2 - 4 years agoHelpfull: Yes(0) No(0)
- log27=1.431
3log3=1.431
log3=0.477
log9=2log3 then 2*o.477=0.954 - 4 years agoHelpfull: Yes(0) No(0)
- C. 0.954
log(9*3)=1.431
log(9)+log(3)=1.431
log 9=1.431-0.477
=0.954 - 4 years agoHelpfull: Yes(0) No(0)
- Log27=3*log3
Log3=1.431/3
Log9=2*log3
=0.954 - 4 years agoHelpfull: Yes(0) No(0)
- log27=3log3
log9=2log3
2log3=3log3-log3=1.431-0.477=0.945 - 2 Months agoHelpfull: Yes(0) No(0)
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