A certain number of men can finish a piece of work in 20 days. However if there were 8 men less it will take 20 days more for the work to be finished. How many men were there originally?
A)115 men B)10 men C)12 men D)8 men

• 20x = 40(x-8)
  x =16
• 4 years agoHelpfull: Yes(2) No(1)
• the original men=x
  8 men less then x-8=20+20=40
  8x=40(x-8)
  40x-8x-320
  32x=320
  x=10
• 3 years agoHelpfull: Yes(0) No(1)
• initial men = x, one day work of 1 man =m;x/m=1/20;m=20x
  x-8/m=1/40; x-8/20x=1/40;x=16men
• 3 years agoHelpfull: Yes(0) No(0)
• Ans. B)10 men;
  if x men can finish the work in 20 days ,
  then 1 man can finish the work in 20*x days,
  so x-8 men can finish the work in (x-8)*20 days which is 40,
  so (x-8)*20 = 40 => x = 10;
• 1 year agoHelpfull: Yes(0) No(0)