If log₁₂27 = a, log₉16 = b, find log₈108.
A)2(a+3)/3b B)2(b+3)/3b C)2(b+3)/3a D)2(a+3)/3a

• Ans:- b
  B is the answer
• 4 years agoHelpfull: Yes(0) No(0)
• Log27/log12=a
  
  3log3/(2log2+log3)=a
  
  3log3/2log2 +3= a
  
  Log16/log9 = b
  
  2log4/2log3= log4/log3= 2log2/log3= b
  
  Log108/log8= log(2²*3³)/log2³
  
  = 2 log2+3log3/(3log2)
  
  = 2/3 + 3log3/3log2
  
  = 2/3 + log3/log2
  
  From solving equation "b"
  We get
  Log2/log3 = b/2
  
  Hence ,2/3+b/2=2(b+3)/3b
• 3 years agoHelpfull: Yes(0) No(0)