Rakesh and Saket run a race of 2 km. First Rakesh gives Saket a start of 200 meters and beats him by 1 minute. If Rakesh gives Saket a start of 6 minutes Rakesh is beaten by 1 km. Find the time in minutes in which Rakesh and Saket can run the races separately.
A)11, 18 B)12, 18 C)8, 10 D)10, 12

• Rakesh and Saket run a race of 2000 m
  
  Rakesh gives Saket a start of 200 meters and beats him by 1 minute.
  
  => Time taken by Ram = T mins
  
  Then time taken by Saket for 2000 - 200 = 1800 m = T + 1 Mins
  
  Speed of Rakesh = 2000/T
  
  Speed of Saket = 1800/(T + 1)
  
  Rakesh gives Saket a start of 6 minutes Rakesh is beaten by 1 km
  
  Time taken by ram to complete = 2000 - 1000 = 1000 m
  
  = 1000/(2000/T)
  
  = T/2 mins
  
  Time is taken by Saket to complete race = T/2 + 6 mins
  
  {1800/(T + 1)} { T/2 + 6} = 2000
  
  => 18( T + 12) = 40(T + 1)
  
  =>18T + 216 = 40T +40
  
  => 22T = 176
  
  => T = 8
  
  time in minutes in which Rakesh races = 8 Min
  
  Speed of Saket= 1800/(T + 1) = 1800/(8 + 1) = 200 m/min
  
  => Time taken by Saket = 2000/200 = 10 min
  
  Rakesh finish in 8 Mins
  
  saket finished in 10 mins
• 3 years agoHelpfull: Yes(3) No(3)
• option c is correct ,
  
  solve using options
• 3 years agoHelpfull: Yes(2) No(7)
• D)10,12
  Rakesh beaten by 1km in 6m
  So sakesh runs 2km in 12mins .
• 3 years agoHelpfull: Yes(1) No(16)