George can do some work in 8 hours. Paul can do some work in 10 hours while Hari can do the same
work in 12 hours. All three of them start working at 9.00 am. While George stops work at 11.00 am
and the remaining two complete the work. Approximately at what time the work be finished?
(a) 11.30 am (b) 12.30 pm
(c) 1 pm (d) 12 noon

• At first George =G,Paul=P, Hari=H
  G=1/8,P=1/10,H=1/12
  LCM(8,10,12)=120
  So that G=8/120=15units of per hour
  Like wise P=12u/h
  H=10u/h
  Then
  At 8:00 to 11:00
  2 hours =2*10+12+15
  =37/120(23/60)
  1-37/120=23/60
  Then after 11:00 G leaves so remaining work is 23
  So
  1/10+1/12=5uld+6uld=11 uld
  So they need 2 hours
  1pm
• 5 Months agoHelpfull: Yes(1) No(0)
• In 2 hours total wrok done by all 3 of 'em is 37/60 {(1/8 + 1/10 + 1/12)*2}
  therefore, remaining is 23/60
  
  now, in 1 hour paul and hari does (1/10 + 1/12) = 22/120 amount of work.
  
  ans-> (23/60) / (22/120)
• 2 Months agoHelpfull: Yes(0) No(0)